From 7e70fb58ae0ac8e5c46f1c54d9cc6a5a1e6500a7 Mon Sep 17 00:00:00 2001
From: augustin64 <me.git@augustin64.fr>
Date: Sat, 30 Nov 2024 10:26:49 +0100
Subject: [PATCH] Update dependencies

---
 DM2.typ | 8 ++++----
 DM3.typ | 2 +-
 DM4.typ | 6 +++---
 DM5.typ | 2 +-
 qcs.typ | 2 +-
 5 files changed, 10 insertions(+), 10 deletions(-)

diff --git a/DM2.typ b/DM2.typ
index 13e5954..9d712b0 100644
--- a/DM2.typ
+++ b/DM2.typ
@@ -10,7 +10,7 @@
 We want to *simplify* the following circuit:
 
 #{
-  import "@preview/quill:0.4.0": *
+  import "@preview/quill:0.5.0": *
 
   quantum-circuit(
     lstick($|v_0〉$), $H$, ctrl(1), $H$, [\ ],
@@ -21,7 +21,7 @@ We want to *simplify* the following circuit:
 The gates 
 
 #{
-  import "@preview/quill:0.4.0": *
+  import "@preview/quill:0.5.0": *
 
   quantum-circuit(
     lstick($$), $H$, rstick($$), [\ ],
@@ -50,7 +50,7 @@ Which gives $cases(
 )$ that corresponds to an *inversed CNOT* that we can denote:
 
 #{
-  import "@preview/quill:0.4.0": *
+  import "@preview/quill:0.5.0": *
 
   quantum-circuit(
     lstick($|v_0〉$), targ(), rstick($$), [\ ],
@@ -66,7 +66,7 @@ Using only $2^n$ queries, all queries could have the same value with $f$ balance
 
 In the *quantum version*, we may use the following circuit:
 #{
-  import "@preview/quill:0.4.0": *
+  import "@preview/quill:0.5.0": *
 
   quantum-circuit(
     lstick($|0〉$), $H$, mqgate($U_f$, n:4), $H$, meter(), setwire(2), rstick($$), [\ ],
diff --git a/DM3.typ b/DM3.typ
index 270b490..4b8ba0a 100644
--- a/DM3.typ
+++ b/DM3.typ
@@ -23,7 +23,7 @@
   ),
   title: "Assignment",
   ([
-    + Starting from state $ket(Phi)= 1/sqrt(2)(ket(00)+ket(11))$, is it true that for any basis ($ket(v_0)$, ket(v_1)), Alice and Bob will get the same outcome ?
+    + Starting from state $ket(Phi)= 1/sqrt(2)(ket(00)+ket(11))$, is it true that for any basis ($ket(v_0), ket(v_1)$), Alice and Bob will get the same outcome ?
     + Show that, for the state $1/sqrt(2)(ket(01)-ket(10))$, the outcome of Alice and Bob are opposite in any basis ($ket(v_0), ket(v_1)$)
   ]),
 )
diff --git a/DM4.typ b/DM4.typ
index 9ed9c35..3e86054 100644
--- a/DM4.typ
+++ b/DM4.typ
@@ -26,7 +26,7 @@
 + $"CNOT"[3,1]$ corresponds to the following circuit:
 
   #{
-    import "@preview/quill:0.4.0": *
+    import "@preview/quill:0.5.0": *
 
     quantum-circuit(
       lstick($v_0$), 1, targ(), 2, rstick($$), [\ ],
@@ -54,7 +54,7 @@
     Let $A=1/sqrt(2) mat(-i,-1;1,i)$ and $B=mat(0,1;-1,0)$.
     Which 2-qubit gate can you apply on the first qubits at the end of the circuit
     #{
-      import "@preview/quill:0.4.0": *
+      import "@preview/quill:0.5.0": *
 
       quantum-circuit(
         lstick($$), ctrl(2), 1, ctrl(2), 1, [\ ],
@@ -80,7 +80,7 @@ Let $D = i I_2$. Then, $C mat(I_2,0,0,0;0,I_2,0,0;0,0,I_2,0;0,0,0,D) = "Toffoli"
 
 Which corresponds to the following circuit:
 #{
-  import "@preview/quill:0.4.0": *
+  import "@preview/quill:0.5.0": *
 
   quantum-circuit(
     lstick($$), ctrl(2), 1, ctrl(2), 1, [\ ],
diff --git a/DM5.typ b/DM5.typ
index 9f100bf..176bde8 100644
--- a/DM5.typ
+++ b/DM5.typ
@@ -17,7 +17,7 @@
 The phase estimation circuit described in class is:
 
 #{
-  import "@preview/quill:0.4.0": *
+  import "@preview/quill:0.5.0": *
 
   quantum-circuit(
     lstick($ket(0)$), $H$, slice(label: $ket(Phi_0)$), ctrl(3, show-dot: false),
diff --git a/qcs.typ b/qcs.typ
index 806704b..9648440 100644
--- a/qcs.typ
+++ b/qcs.typ
@@ -1,4 +1,4 @@
-#import "@preview/showybox:2.0.1": showybox
+#import "@preview/showybox:2.0.3": showybox
 #import "@preview/physica:0.9.3": *
 
 #let question(title, content) = {