pieuvre/main.ml

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OCaml
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open Affichage
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open Typing
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type entry =
Simple of Lam.lam
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| Reduce of Lam.lam
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| AlphaEquiv of Lam.lam * Lam.lam
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let beta_reduce e =
let rec aux = function
Some e ->
print_expr e;
print_newline ();
aux (Lam.betastep e);
| None -> ()
in print_expr e;
print_newline ();
let e = Lam.alpha_convert e in
print_expr e;
print_newline ();
aux (Lam.betastep e)
let alpha_get_lam where_from =
let input_str = In_channel.input_all where_from in
match Str.split (Str.regexp "&") input_str with
[s1; s2] -> AlphaEquiv (
Parser.main Lexer.token (Lexing.from_string (s1^"\n")),
Parser.main Lexer.token (Lexing.from_string s2)
)
| _ -> failwith "Alpha-equivalence: nombre de delimiteurs incorrect"
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let interpret e =
begin
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print_expr e;
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print_newline();
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print_ty (typeinfer [] e);
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print_newline()
end
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let nom_fichier = ref ""
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let reduce = ref false
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let alpha = ref false
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let equiv_fichier = ref ""
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let parse_channel c =
let lexbuf = Lexing.from_channel c in
Parser.main Lexer.token lexbuf
let recupere_entree () =
let optlist = [
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("-alpha",
Arg.Set alpha,
"Vérifie l'alpha équivalence de deux termes séparés par &");
("-reduce",
Arg.Set reduce,
"Affiche les réductions successives du lambda-terme")
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] in
let usage = "Bienvenue à bord." in (* message d'accueil, option -help *)
Arg.parse (* ci-dessous les 3 arguments de Arg.parse : *)
optlist (* la liste des options definie plus haut *)
(fun s -> nom_fichier := s) (* la fonction a declencher lorsqu'on recupere un string qui n'est pas une option : ici c'est le nom du fichier, et on stocke cette information dans la reference nom_fichier *)
usage; (* le message d'accueil *)
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try
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let where_from = match !nom_fichier with
| "" -> stdin
| s -> open_in s in
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if !alpha
then alpha_get_lam where_from
else if !reduce
then Reduce (parse_channel where_from)
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else Simple (parse_channel where_from)
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with e -> (Printf.printf "problème de saisie\n"; raise e)
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(* la fonction principale *)
let run () =
try
match recupere_entree () with
Simple l -> let _ = interpret l in ()
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| Reduce l -> let _ = beta_reduce l in ()
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| AlphaEquiv (l1, l2) -> begin
if ((Lam.(=~)) l1 l2) then
print_string "true\n"
else
print_string "false\n"
end;
flush stdout
with e -> raise e
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let _ = run ()
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